相关算法的原理参考Ronny，地址：图像分析：投影曲线的波峰查找，这里感谢下原作者。
参照C++的代码实现，我用C#翻译了下，其实原理也很简单的，下面放相关实现代码：
private double[] oneDiff(double[] data) {double[] result = new double[data.Length - 1];for (int i = 0; i < result.Length; i++){result[i] = data[i + 1] - data[i];}return result;}private int[] trendSign(double[] data){int[] sign = new int[data.Length];for (int i = 0; i < sign.Length; i++){if (data[i] > 0) sign[i] =1;else if (data[i] == 0) sign[i] = 0;else sign[i] = -1;}for (int i = sign.Length - 1; i >=0 ; i--){if (sign[i] == 0 && i ==sign.Length - 1){sign[i] = 1;}else if (sign[i] == 0) {if (sign[i+1] >= 0){sign[i] = 1;}else{sign[i] = -1;}}}return sign;}private int[] getPeaksIndex(int[] diff) {List<int> data = new List<int>();for (int i = 0; i != diff.Length - 1; i++){if (diff[i+1] - diff[i] == -2){data.Add(i + 1);}}int[] result = new int[data.Count];for (int i = 0; i < result.Length; i++){result[i] = data[i];}return result;//相当于原数组的下标}
调用方法：
double[] data = {25, 8, 15, 5, 6, 10, 10, 3, 1, 20, 7}; int[] index = getPeaksIndex(trendSign(oneDiff(Constant.data)));
返回的int[]数组内容是对应原数组中峰值对应的索引(从0开始)