为什么80%的码农都做不了架构师？>>> 
发布/ 订阅者模式（Publish/Subscribe）有两个参与者：发布者和订阅者。发布者创建某个信息，订阅者绑定这个信道，当发布者有消息发布至该信道时，订阅者就会接收到一个通知。最重要的一点是，发布者和订阅者是完全解耦的，彼此并不知晓对方的存在一种消息模式。
订阅发布者
我们创建一个简单的订阅发布者，基本的4个方法：
registerSubscriber 注册订阅者
removeSubscriber 订阅的取消
publish 消息推送
sortList 消息推送排序
class DispatcherPattern
{protected $subList = array();public function registerSubscriber($name, $callback){$this->subList[$name] = $callback;}public function removeSubscriber($name){if (isset($this->subList[$name])) {unset($this->subList[$name]);}}public function publish($params){if (empty($this->subList) || !is_array($this->subList)) {return 'null';}foreach ($this->subList as $callback) {call_user_func_array($callback, $params);}}public function sortList(){ksort($this->subList);}
}订阅体
接着我们创建一个用户对象,用户对象有增加积分的功能
class User
{protected $name;public function __construct($name){$this->name = $name;}public function addScore($score){printf( $this->name . ' add Score :' . $score . "\r\n");}
}通过订阅发布者模式为用户增加积分
$score = 1;$dispatcher = new DispatcherPattern();$dispatcher->registerSubscriber('0', function()
{printf( "this is first handle \r\n");
});$dispatcher->registerSubscriber('3', array(new User('user3'), 'addScore'));
$dispatcher->registerSubscriber('1', array(new User('user1'), 'addScore'));
$dispatcher->registerSubscriber('2', array(new User('user2'), 'addScore'));$dispatcher->removeSubscriber('2');$dispatcher->sortList();
$dispatcher->publish(array($score));result:
this is first handle
user1 add Score :1
user3 add Score :1