如何扫描一个网站的漏洞百度网页版入口链接

最近项目中有需求，需要添加功能引导，如果用户是第一次使用，那么就显示功能引导，之后则不再显示。感觉这样的需求正好可以利用ViewStub来实现，更节省资源。

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"android:layout_width="match_parent"android:layout_height="match_parent" >..............<ViewStub android:layout_width="match_parent"android:layout_height="match_parent"android:id="@+id/lay_guide"android:layout="@layout/guide_main_tab"/></RelativeLayout>

if(!GuidePreference.isGuide(getApplicationContext(), GuidePreference.MAIN_TAB_V4)){ViewStub stub = (ViewStub) findViewById(R.id.lay_guide);
　　if(stub==null){
　　　　return ;}mFilpper = (ViewFlipper) stub.inflate() ;mFilpper.setOnClickListener(new View.OnClickListener() {@Override
　　　　public void onClick(View v) {guideSwitch() ;}});
}

查看ViewStub的源码，inflate()部分如下：

public View inflate() {final ViewParent viewParent = getParent();if (viewParent != null && viewParent instanceof ViewGroup) {if (mLayoutResource != 0) {final ViewGroup parent = (ViewGroup) viewParent;final LayoutInflater factory;if (mInflater != null) {factory = mInflater;} else {factory = LayoutInflater.from(mContext);}final View view = factory.inflate(mLayoutResource, parent,false);if (mInflatedId != NO_ID) {view.setId(mInflatedId);}final int index = parent.indexOfChild(this);parent.removeViewInLayout(this);final ViewGroup.LayoutParams layoutParams = getLayoutParams();if (layoutParams != null) {parent.addView(view, index, layoutParams);} else {parent.addView(view, index);}mInflatedViewRef = new WeakReference<View>(view);if (mInflateListener != null) {mInflateListener.onInflate(this, view);}return view;} else {throw new IllegalArgumentException("ViewStub must have a valid layoutResource");}} else {throw new IllegalStateException("ViewStub must have a non-null ViewGroup viewParent");}}

从以上代码可以看出，ViewStub其实只相当于一个占位View而已，在未inflate之前，高宽都是0，只保存了在parent中的index和layoutParmas而已，在inflate时，用mLayoutResource来替换掉自己。这比自己平时动态往ViewGroup里面添加view的确要少一些操作，方便多了。