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习题11-8 单链表结点删除 (20 分)
本题要求实现两个函数,分别将读入的数据存储为单链表、将链表中所有存储了某给定值的结点删除。链表结点定义如下:
struct ListNode {int data;ListNode *next;
};
函数接口定义:
struct ListNode *readlist();
struct ListNode *deletem( struct ListNode *L, int m );
函数readlist从标准输入读入一系列正整数,按照读入顺序建立单链表。当读到−1时表示输入结束,函数应返回指向单链表头结点的指针。
函数deletem将单链表L中所有存储了m的结点删除。返回指向结果链表头结点的指针。
裁判测试程序样例:
#include <stdio.h>
#include <stdlib.h>struct ListNode {int data;struct ListNode *next;
};struct ListNode *readlist();
struct ListNode *deletem( struct ListNode *L, int m );
void printlist( struct ListNode *L )
{struct ListNode *p = L;while (p) {printf("%d ", p->data);p = p->next;}printf("\n");
}int main()
{int m;struct ListNode *L = readlist();scanf("%d", &m);L = deletem(L, m);printlist(L);return 0;
}/* 你的代码将被嵌在这里 */
输入样例:
10 11 10 12 10 -1
10
输出样例:
11 12
struct ListNode *readlist()
{struct ListNode *head, *tail, *p;int n = 0;head = NULL;tail = head;while(n != -1){scanf("%d",&n);if(n != -1){p = (struct ListNode*)malloc(sizeof(struct ListNode));p -> data = n;p -> next = NULL;if(head == NULL){head = p;}else{tail -> next = p;}tail = p;}}return head;
}struct ListNode *deletem( struct ListNode *L, int m )
{struct ListNode *pre = NULL, *op = NULL;while(L != NULL && L -> data == m) L = L -> next;if(L == NULL) return NULL;pre = L;op = pre -> next;while(op != NULL){if(op -> data == m){while(op != NULL && op -> data == m){op = op -> next;}if(op == NULL) pre -> next = op;else{pre -> next = op;pre = pre -> next;op = op -> next;}}else{pre = pre -> next;op = op -> next;}}return L;
}