价格划算的做网站seo推广一个月见效

需求：
一个字符串以空格为单词间分隔符，给定单词的起始位置，依次输出所有单词，注意是环形输出。
例如：
字符串：“i love software testing”
单词数：4
单词起始位置：0
如果给定起始位置是0，则输出：
i love software testing
如果给定起始位置是1，则输出：
love software testing i
以此类推。。。

思路：
给定字符串，要分离出单词位置，对于单词环形输出，有2种方案。

1. 以给定的序号开始，先输出剩余字符串，再输出序号之前的字符串，这是常规思路。
2. 考虑环形特性，序号除单词个数取余数，如果余数再次等于给定的序号数，则便是第二次遍历开始。
   例如：
   给定字符串：i love software war
   则单词序号：i[0] love[1] software[2] war[3]
   给定起始序号：2
   则：2%4=2，输出 software，序号+1
   3%4=3，输出 war， 序号+1
   4%4=0， 输出 i， 序号+1
   5%4=1，输出love， 序号+1
   6%2=2，跟给定的初始序号重复，则结束。

实现：
常规实现：

public static void printWordsInCircularOrder1(String str, int index) {String[] strArray = str.trim().split(" ");if (index >= 0 && index < strArray.length) {for (int i = index; i < strArray.length; i++) {System.out.print(strArray[i] + " ");}for (int j = 0; j < index; j++) {System.out.print(strArray[j] + " ");}System.out.println();} else {System.out.println("invalid index");}}

环形特性实现：

 public static void printWordsInCircularOrder2(String str, int index) {String[] strArray = str.split(" ");int tempIndex = index;if (index >= 0 && index < strArray.length) {do {System.out.print(strArray[tempIndex % strArray.length] + " ");tempIndex++;} while (tempIndex % strArray.length != index);System.out.println();} else {System.out.println("Invalid index");}
}

全部代码：

import java.util.Scanner;public class Test {public static void main(String[] args) {testPrintWordInCircularOrder();}public static void testPrintWordInCircularOrder() {System.out.println("Enter a string: ");Scanner in = new Scanner(System.in);String str = in.nextLine();System.out.println("Enter an index number, -1 means to quit");int index = in.nextInt();while (index != -1) {printWordsInCircularOrder2(str, index);System.out.println("Enter an index number, -1 means to quit");index = in.nextInt();}}public static void printWordsInCircularOrder1(String str, int index) {String[] strArray = str.trim().split(" ");if (index >= 0 && index < strArray.length) {for (int i = index; i < strArray.length; i++) {System.out.print(strArray[i] + " ");}for (int j = 0; j < index; j++) {System.out.print(strArray[j] + " ");}System.out.println();} else {System.out.println("invalid index");}}public static void printWordsInCircularOrder2(String str, int index) {String[] strArray = str.split(" ");int tempIndex = index;if (index >= 0 && index < strArray.length) {do {System.out.print(strArray[tempIndex % strArray.length] + " ");tempIndex++;} while (tempIndex % strArray.length != index);System.out.println();} else {System.out.println("Invalid index");}}
}

结果：

Enter a string: 
I Love Software Testing
Enter an index number, -1 means to quit
0
I Love Software Testing 
Enter an index number, -1 means to quit
1
Love Software Testing I 
Enter an index number, -1 means to quit
2
Software Testing I Love 
Enter an index number, -1 means to quit
3
Testing I Love Software 
Enter an index number, -1 means to quit
4
Invalid index
Enter an index number, -1 means to quit
-1Process finished with exit code 0